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CAT 1993 — QA Question 29

Basics of TrianglesEasy
Passage / Data

Answer the following questions based on the information given below:

ABC forms an equilateral triangle in which B is 2 km from A. A person starts walking from B in a direction parallel to AC and stops when he reaches a point D directly east of C. He, then, reverses direction and walks till he reaches a point E directly south of C.

The total distance walked by the person is

Answer & solution

  • A

    3 km

  • B

    4 km

  • C

    23 km

  • 6 km

Solution

Consider the solution to previous question of this set.

Hence, the total distance walked by the person = BD + DB + BE = 2 + 2 + 2 = 6 km.

Hence, option (d).

CAT 1993 QA Q29: The total distance walked by the person is — Solution | TheCATExam