CAT 1993 — QA Question 31
Answer the following questions based on the information given below:
ABC forms an equilateral triangle in which B is 2 km from A. A person starts walking from B in a direction parallel to AC and stops when he reaches a point D directly east of C. He, then, reverses direction and walks till he reaches a point E directly south of C.
Let x < 0.50, 0 < y < 1, z > 1. Given a set of numbers, the middle number, when they are arranged in ascending order, is called the median. So the median of the numbers x, y, and z would be
Answer & solution
- A
less than one
between 0 and 1
- C
greater than 1
- D
cannot say
Since there are two numbers which are less than 1 (viz. x and y), it is obvious that the median will be less than 1.
Hence, option (c) cannot be the answer.
Since x < 0.5 and 0 < y < 1, the median will not be less than 0.
Hence, option (b).