CAT 1994QA Question 23

Relative SpeedEasy

A and B walk from X to Y, a distance of 27 km at 5 kmph and 7 kmph respectively. B reaches Y and immediately turns back meeting A at Z. What is the distance from X to Z?

Answer & solution

Correct answer: 22.5 km

  • A

    25 km

  • 22.5 km

  • C

    24 km

  • D

    20 km

Solution

Let they meet at a distance x kms from X.
So the total distance travelled by A = x at the speed of 5 kmph.
Total distance travelled by B = 27 + (27 – x) = (54 – x) at the speed of 7 kmph.
Time taken by A = x5.

Time taken by B = (54-x)7

Since they have met at the same time, they would have travelled for the same time. Hence x5=(54-x)7 or x = 22.5 kms.

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CAT 1994 QA Q23: A and B walk from X to Y, a distance of 27 km at 5 kmph and 7 kmph respectively. B reaches Y and immediately t — Solution | TheCATExam