CAT 1995QA Question 16

PercentageEasy
Passage / Data

Direction: Answer the questions based on the following information.
Four sisters — Suvarna, Tara, Uma and Vibha are playing a game such that the loser doubles the money of each of the other players from her share. They played four games and each sister lost one game in alphabetical order. At the end of fourth game, each sister had Rs.32.

25 of the voters promise to vote for P and the rest promised to vote for Q. Of these, on the last day 15% of the voters went back of their promise to vote for P and 25% of voters went back of their promise to vote for Q, and P lost by 2 votes. Then the total number of voters is

Answer & solution

  • 100

  • B

    110

  • C

    90

  • D

    95

Solution

Let there be 100 voters in all.
Initially, 40 of these promised to vote for P, while 60 of them promised to vote for Q.
On the last day, (15% of 40) = 6 voters went back of their promise and voted for Q.
Also, 25% of 60 = 15 voters shifted their interest from Q to P.
So finally, P end up getting (40 – 6 + 15) = 49 votes and
Q end up getting (60 – 15 + 6) = 51 votes.
Hence, margin of victory for Q = (51 – 49) = 2, which is true. Hence, there were 100 voters in all.

CAT 1995 QA Q16: 2 5 of the voters promise to vote for P and the rest promised to vote for Q. Of these, on the last day 15% of — Solution | TheCATExam