CAT 1998QA Question 9

Numbers (P&C)Easy

How many numbers can be formed from 1, 2, 3, 4, 5, without repetition, when the digit at the unit’s place must be greater than that in the ten’s place?

Answer & solution

Correct answer: 60

  • A

    54

  • 60

  • C

    17

  • D

    2 × 4!

Solution

   tTen's place uUnit's place

u > t

Case (i): t = 1
u can be 2, 3, 4, 5 ⇒ 4 possibilities
So total possible number that can be formed
= 4 × 3 × 2 × 1
Case (ii): t = 2
u can be 3, 4, 5 ⇒ 3 possibilities
So total possible number that can be formed
= 3 × 3 × 2 × 1
Case (iii): t = 3
u can be 4, 5 ⇒ 2 possibilities
So total possible number that can be formed
= 2 × 3 × 2 × 1
Case (iv): t = 4
u can be 5 ⇒ 1 possibility
So total possible number that can be formed
= 1 × 3 × 2 × 1
Hence, total possible number = (4 + 3 + 2 + 1) 3 = 60

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CAT 1998 QA Q9: How many numbers can be formed from 1, 2, 3, 4, 5, without repetition, when the digit at the unit’s plac — Solution | TheCATExam