CAT 1998 — QA Question 9
Numbers (P&C)Easy
How many numbers can be formed from 1, 2, 3, 4, 5, without repetition, when the digit at the unit’s place must be greater than that in the ten’s place?
Answer & solution
Correct answer: 60
- A
54
60
- C
17
- D
2 × 4!
Solution
u > t
Case (i): t = 1
u can be 2, 3, 4, 5 ⇒ 4 possibilities
So total possible number that can be formed
= 4 × 3 × 2 × 1
Case (ii): t = 2
u can be 3, 4, 5 ⇒ 3 possibilities
So total possible number that can be formed
= 3 × 3 × 2 × 1
Case (iii): t = 3
u can be 4, 5 ⇒ 2 possibilities
So total possible number that can be formed
= 2 × 3 × 2 × 1
Case (iv): t = 4
u can be 5 ⇒ 1 possibility
So total possible number that can be formed
= 1 × 3 × 2 × 1
Hence, total possible number = (4 + 3 + 2 + 1) = 60