CAT 1999 — QA Question 34
Directions: Answer the questions based on the following information.
There are 50 integers a1, a2 … a50, not all of them necessarily different. Let the greatest integer of these 50 integers be referred to as G, and the smallest integer be referred to as L. The integers a1 through a24 form sequence S1, and the rest form sequence S2. Each member of S1 is less than or equal to each member of S2.
Every element of S1 is made greater than or equal to every element of S2 by adding to each element of S1 an integer x. Then x cannot be less than
Answer & solution
- A
210
- B
the smallest value of S2
- C
the largest value of S2
(G – L)
Since every element of S1 is less than or equal to each member of S2, L will be in S1 and G in S2.
For some i (1≤ i ≤ 24), ai = L and for some j (25 ≤ j ≤ 50), aj = G.
Every other element of S1 is greater than ai and every other member of S2 is less than aj.
Therefore, to make every element of S1 greater than or equal to that of S2, we need to add a minimum of (aj –ai) = G – L.