CAT 2001 — DILR Question 44
Answer the following question based on the information given below.
A and B are two sets (e.g. A = mothers, B = women). The elements that could belong to both the sets (e.g. women who are mothers) is given by the set C = A.B. The elements which could belong to either A or B, or both, is indicated by the set D = A ∪ B. A set that does not contain any elements is known as a null set, represented by Ï (for example, if none of the women in the set B is a mother, they C = A.B is a null set, or C = Ï).
Let 'V' signify the set of all vertebrates; 'M' the set of all mammals; 'D' dogs; 'F' fish; 'A' Alsatian and 'P', a dog named Pluto.
If 09/12/2001 happens to be Sunday, then 09/12/1971 would have been a
Answer & solution
- A
Wednesday
- B
Tuesday
- C
Saturday
Thursday
A normal year has 52 weeks and 1extra day.
∴ 365 = 52 × 7 + 1
A leap year has 52 weeks and 2 extra days.
∴ 366 = 52 × 7 + 2
There are 30 extra days between 1971 and 2001.
In this period there were 8 leap years, therefore another 8 extra days.
∴ 38 = 7 × 5 + 3
∴ We are left with 3 extra days.
If 9/12/2001 is a Sunday, then 12/12/1971 was a Sunday and 9/12/1971 was a Thursday.
[3 days before Sunday is Thursday since we are going back in time.]
Hence, option (d).