CAT 2001 — QA Question 26
Inequality Maximization / MinimizationEasy
If a, b, c and d are four positive real numbers such that abcd = 1, what is the minimum value of (1 + a)(1 + b)(1 + c)(1 + d)?
Answer & solution
- A
4
- B
1
16
- D
18
Solution
This is possible when, a = b = c = d = 1
âµ a, b, c, d are positive real numbers
∴ (1 + a)(1 + b)(1 + c)(1 + d) = 2 × 2 × 2 × 2 = 16
Hence, option (c).