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CAT 2003 Slot 2 — QA Question 25

Simple EquationsEasy

Using only 2, 5, 10, 25 and 50 paise coins, what will be the minimum number of coins required to pay exactly 78 paise, 69 paise and Rs 1.01 to three different persons?

Answer & solution

Correct answer: 19

  • 19

  • B

    20

  • C

    17

  • D

    18

Solution

Case1: To pay 78 paise using minimum number of coins:

78 = 1(50) + 2(10) + 4(2), i.e. a total of 7 coins were used

Case 2: To pay 69 paise using minimum number of coins:

69 = 1(50) + 1(10) + 1(5) + 2(2), i.e. a total of 5 coins were used

Case 3: To pay 101 paise using minimum number of coins:

101 = 1(50)  + 1(25) + 2(10) + 3(2), i.e. a total of 7 coins were used

∴ Minimum coins used were 7 + 5 + 7 = 19 coins

Hence, option (a).

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CAT 2003 Slot 2 QA Q25: Using only 2, 5, 10, 25 and 50 paise coins, what will be the minimum number of coins required to pay exactly 7 — Solution | TheCATExam