CAT 2006QA Question 3

RatioEasy

If ab=13bc=2cd=12de=3 and ef=14 then what is the value of abcdef?

Answer & solution

Correct answer: 3 8

  • 38

  • B

    278

  • C

    34

  • D

    274

  • E

    14

Solution

ad = ab×bc×cd = 13×2×12 = 13

be = bc×cd×de = 2×12×3 = 3

cf = cd×de×ef = 12×3×14 = 38

∴ abcdef = 13×3×38 = 38

Hence, option (a).

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CAT 2006 QA Q3 — Ratio solution | TheCATExam