CAT 2017 Slot 2QA Question 11

RatioEasy

If a, b, c are three positive integers such that a and b are in the ratio 3 : 4 while b and c are in the ratio 2 : 1, then which one of the following is a possible value of (a + b + c)?

Answer & solution

Correct answer: 207

  • A

    201

  • B

    205

  • 207

  • D

    210

Solution

Easy

Merge the two pairwise ratios into a single a:b:ca:b:c. Their sum is then a fixed multiple of an integer, so the answer must be that multiple — only one option qualifies.

1

Combine the ratios. a:b=3:4a:b=3:4 and b:c=2:1b:c=2:1. Make bb common (scale the second by 22 to 4:24:2).

a:b:c=3:4:2\begin{aligned} &a:b:c=3:4:2 \end{aligned}
2

Form the sum. Write a=3k, b=4k, c=2ka=3k,\ b=4k,\ c=2k for a positive integer kk.

a+b+c=3k+4k+2k=9k\begin{aligned} &a+b+c=3k+4k+2k=9k \end{aligned}
3

Match the options. The sum must be a multiple of 99. Checking digit sums: only 207207 works (2+0+7=92+0+7=9).

207=9×23(k=23) 201,205,210 are not multiples of 9\begin{aligned} &207=9\times 23 \quad\text{(}k=23\text{)}\\ &\Rightarrow\ 201,205,210 \text{ are not multiples of }9 \end{aligned}
a+b+c=207a+b+c=207

Related Ratio questions

See all Ratio, Proportion & Variation questions →
CAT 2017 Slot 2 QA Q11: If a, b, c are three positive integers such that a and b are in the ratio 3 : 4 while b and c are in the ratio — Solution | TheCATExam