CAT 2018 Slot 1QA Question 2

Basics of TSD/ProportinalityEasy

Point P lies between points A and B such that the length of BP is thrice that of AP. Car 1 starts from A and moves towards B. Simultaneously, car 2 starts from B and moves towards A. Car 2 reaches P one hour after car 1 reaches P. If the speed of car 2 is half that of car 1, then the time, in minutes, taken by car 1 in reaching P from A is

Answer & solution

Answer: 12

Solution

Let distance between A and P be ‘x’ kms. Therefore, distance between P and B = (3x) kms

Let car 1 reaches point P in ‘t’ minutes. Therefore, car 2 takes (t + 60) minutes to reach P.

Speed of car 1 = x/t and speed of car 2 = 3x/(t + 60)

Hence, x2t = 3xt+60

Solving this, we get

t = 12 minutes.

Hence, 12.