CAT 2018 Slot 1QA Question 28

Number TheoryEasy

While multiplying three real numbers, Ashok took one of the numbers as 73 instead of 37. As a result, the product went up by 720. Then the minimum possible value of the sum of squares of the other two numbers is

Answer & solution

Answer: 40

Solution

Let X and Y are the two real numbers.

X × Y × 73 − X × Y × 37 = 720

X × Y × (73 – 37) = 720

X × Y × 36 = 720

X × Y = 20

AM(X2, Y2) ≥ GM(X2, Y2)

∴ X2+Y22 ≥ X2×Y2

∴ (X2 + Y2) ≥ 40

Alternately
We know, X × Y = 40

Also, (X - Y)2 ≥ 0 [Square of any number is always greater than or equal to zero]

∴ X2 + Y2 - 2XY ≥ 0

∴ X2 + Y2 ≥ 2XY

∴ X2 + Y2 ≥ 40

Hence, 40.

CAT 2018 Slot 1 QA Q28: While multiplying three real numbers, Ashok took one of the numbers as 73 instead of 37. As a result, the prod — Solution | TheCATExam