CAT 2018 Slot 1 — QA Question 32
Given an equilateral triangle T1 with side 24 cm, a second triangle T2 is formed by joining the midpoints of the sides of T1. Then a third triangle T3 is formed by joining the midpoints of the sides of T2. If this process of forming triangles is continued, the sum of the areas, in sq cm, of infinitely many such triangles T1, T2, T3,... will be
Answer & solution
- A
248√3
- B
164√3
- C
188√3
192√3

Consider âABC (i.e. T1) and âDEF (i.e., T2).
D and E are midpoints of AB and AC respectively. Therefore, BC = 2 × DE
Side of T2 = 1/2 × Side of T1
Area of T1 = A(T1) = √3/4 × 242
Similarly, A(T2) = √3/4 × 122
A(T3) = √3/4 × 62 ... and so on
Sum of areas of infinitely many Ti’s
= √3/4 × 242 + √3/4 × 122 + √3/4 × 62 + ...
= √3/4 (242 + 122 + 62 + ...)
Here, (242 + 122 + 62 + ...) is an infinite series with r = 1/4
Hence, = √3/4 (242 + 122 + 62 + ...) = = 192√3
Hence, option (d).