CAT 2019 Slot 2QA Question 17

Percentage ChangeEasy

In an examination, the score of A was 10% less than that of B, the score of B was 25% more than that of C, and the score of C was 20% less than that of D. If A scored 72, then the score of D was

Answer & solution

Answer: 80

Solution

Easy

Translate each comparison into a multiplier and chain them. Work back from A=72A=72 to BB, then CC, then DD.

1

AA is 10%10\% less than BB. So A=0.9BA=0.9\,B.

B=720.9=80\begin{aligned} &B=\frac{72}{0.9}=80 \end{aligned}
2

BB is 25%25\% more than CC. So B=54CB=\tfrac{5}{4}C.

C=45×80=64\begin{aligned} &C=\frac{4}{5}\times 80=64 \end{aligned}
3

CC is 20%20\% less than DD. So C=45DC=\tfrac{4}{5}D.

D=54×64=80\begin{aligned} &D=\frac{5}{4}\times 64=80 \end{aligned}
D=80D=80
CAT 2019 Slot 2 QA Q17: In an examination, the score of A was 10% less than that of B, the score of B was 25% more than that of C, and — Solution | TheCATExam