Easy
Substitute k=5x−1 and m=3y so both equations become linear in k,m. Note 5x=5⋅5x−1=5k and 3y+1=3⋅3y=3m. Solve the linear system, then read off x and y from the powers.
1
Linearise. Let k=5x−1 and m=3y.
5x−3y=13438⇒5k−m=13438(1)5x−1+3y+1=9686⇒k+3m=9686(2)
2
Eliminate m. Multiply (1) by 3 and add to (2).
15k−3m=40314[3×(1)]⇒ 16k=50000[+(2)]⇒ k=3125=55
3
Recover x and y. From k=5x−1=55 and equation (2).
5x−1=55⇒x=63m=9686−3125=6561⇒m=2187=373y=37⇒y=7
x+y=6+7=13