A circle of diameter 8 inches is inscribed in a triangle ABC where ∠ABC = 90°. If BC = 10 inches then the area of triangle in square inches is.
Answer & solution
Answer: 120
Solution
Easy
Use the tangent-length property of an inscribed circle: the two tangents drawn from any external vertex are equal. With the incircle radius =4 (diameter 8) and the right angle at B, label the equal tangent segments and use the Pythagorean theorem to find the unknown.
1
Tangent lengths from B. The incircle has radius r=4. Where it touches BA and BC, the two tangents from B are equal; since the angle at B is 90∘, those tangent lengths each equal the radius.
BM=BN=4(tangents from B,∠B=90∘)
2
Tangent lengths from C and A. From C: the tangent along BC is BC−BM=10−4=6, so the tangent from C on CA is also 6. Let the tangent length from A be x (so AN=x on AB and x on CA).
Compute the area. The legs are AB=x+4=24 and BC=10.
Area=21⋅AB⋅BC=21⋅24⋅10=120
120sq inches
For a right triangle, the inradius is r=2leg1+leg2−hyp. With r=4,BC=10 and legs 10,AB: 4=210+AB−AB2+100 gives AB=24, so area =21⋅24⋅10=120.
CAT 2021 Slot 1 QA Q15: A circle of diameter 8 inches is inscribed in a triangle ABC where ∠ABC = 90°. If BC = 10 inches then — Solution | TheCATExam