CAT 2022 Slot 2QA Question 8

Working in ShiftsEasy

Working alone, the times taken by Anu, Tanu and Manu to complete any job are in the ratio 5 : 8 : 10. They accept a job which they can finish in 4 days if they all work together for 8 hours per day. However, Anu and Tanu work together for the first 6 days, working 6 hours 40 minutes per day. Then, the number of hours that Manu will take to complete the remaining job working alone is:

Answer & solution

Answer: 6

Solution

Easy

Convert the time ratio into an efficiency (work-per-hour) ratio by inverting it. Find the total work from the "all three for 44 days ×\times 88 h" condition, subtract what Anu and Tanu do in 66 days, and let Manu mop up the rest.

1

Efficiencies are reciprocals of times 5:8:105:8:10:

15:18:110=8:5:4(multiply by LCM 40).\frac15:\frac18:\frac1{10}=8:5:4 \quad(\text{multiply by LCM }40).

Let efficiencies be 8x,5x,4x8x,5x,4x units per hour.

2

Total work (all three, 44 days, 88 h/day):

(8x+5x+4x)×4×8=17x×32=544x.(8x+5x+4x)\times4\times8=17x\times32=544x.
3

Work by Anu + Tanu for 66 days at 66 h 4040 min =623=203=6\tfrac23=\tfrac{20}{3} h/day:

(8x+5x)×6×203=13x×40=520x.(8x+5x)\times6\times\frac{20}{3}=13x\times40=520x.
4

Manu finishes the remaining 544x520x=24x544x-520x=24x at 4x4x per hour:

24x4x=6 hours.\frac{24x}{4x}=6\ \text{hours}.

Manu needs 6\mathbf{6} hours.

CAT 2022 Slot 2 QA Q8: Working alone, the times taken by Anu, Tanu and Manu to complete any job are in the ratio 5 : 8 : 10. They acc — Solution | TheCATExam