CAT 2023 Slot 3QA Question 20

Arithmetic ProgressionEasy

Let an = 46 + 8n and bn = 98 + 4n be two sequences for natural numbers n ≤ 100. Then, the sum of all terms common to both the sequences is

Answer & solution

  • A

    14798

  • B

    14602

  • 14900

  • D

    15000

Solution

Easy

Both are arithmetic progressions. Their common terms form a new AP whose common difference is lcm\operatorname{lcm} of the two common differences. Find the first common term and the range, then sum the AP.

1

List the two sequences for 1n1001\le n\le 100 (note ana_n uses n99n\le 99 to stay within range too, but the overlap is what matters):

an=46+8n: 54,62,70,,838(d=8)bn=98+4n: 102,106,110,,498(d=4)\begin{aligned} &a_n=46+8n:\ 54,\,62,\,70,\,\dots,\,838\quad(d=8)\\ &b_n=98+4n:\ 102,\,106,\,110,\,\dots,\,498\quad(d=4) \end{aligned}
2

Common difference of the overlap =lcm(8,4)=8=\operatorname{lcm}(8,4)=8. The first term common to both is 102102. So the common terms are:

102,110,118,(d=8)102,\,110,\,118,\,\dots\quad(d=8)
3

Find how many common terms there are. They cannot exceed bnb_n's top value 494494 (the largest term of bnb_n that is also 838\le 838); solving 102+8(k1)494102+8(k-1)\le 494:

102+8(k1)494  8(k1)392 k149  k50\begin{aligned} &102+8(k-1)\le 494\ \Rightarrow\ 8(k-1)\le 392\\ &\Rightarrow\ k-1\le 49\ \Rightarrow\ k\le 50 \end{aligned}

So there are 5050 common terms, last one =494=494.

4

Sum the AP of 5050 terms:

S=502(102+494)=25×596=14900S=\frac{50}{2}\,(102+494)=25\times 596=14900
sum of common terms=14900\text{sum of common terms}=\mathbf{14900}
CAT 2023 Slot 3 QA Q20: Let a n = 46 + 8n and b n = 98 + 4n be two sequences for natural numbers n ≤ 100. Then, the sum of all term — Solution | TheCATExam