XAT 2015 — QA & DI Question 14
Inequality Maximization / MinimizationEasy
If a, b, c and d are four different positive integers selected from 1 to 25, then the highest possible value of ((a + b) + (c + d))/((a + b) + (c – d)) would be:
Answer & solution
- A
47
- B
49
51
- D
96
- E
None of the above
Solution
Let a + b + c = X
We need to find the maximum value of:
and X is minimum possible.
∴ d = 25 and X = 26
The highest possible value of the given expression = 1 + (2 × 25) = 51
Hence, option (c).