XAT 2017QA & DI Question 4

Basics of CirclesEasy

AB is a chord of a circle. The length of AB is 24 cm. P is the midpoint of AB. Perpendiculars from P on either side of the chord meets the circle at M and N respectively. If PM < PN and PM = 8 cm. then what will be the length of PN?

Answer & solution

  • A

    17 cm

  • 18 cm

  • C

    19 cm

  • D

    20 cm

  • E

    21 cm

Solution

Let us draw the diagram using the given conditions.

​​​​​​​

AB = 24 cm and P is the mid-point of AB. 

∴ AP = PB = 12 cm.

MN is perpendicular to AB and passes through P. 

PM < PN. 

∴ M should be closer to A and B than N.

MN and AB are 2 perpendicular chords intersecting at P. 

Therefore, according to the intersecting chords theorem, AP × PB = PM × PN

⇒ 12 × 12 = 8 × PN

⇒ PN = 18 cm.

Hence, option (b).

XAT 2017 QA & DI Q4: AB is a chord of a circle. The length of AB is 24 cm. P is the midpoint of AB. Perpendiculars from P on either — Solution | TheCATExam