XAT 2017 — QA & DI Question 7
Arup and Swarup leave point A at 8 AM to point B. To reach B, they have to walk the first 2 km, then travel 4 km by boat and complete the final 20 km by car. Arup and Swarup walk at a constant speed of 4 km/hr and 5 km/hr respectively. Each rows his boat for 30 minutes. Arup drives his car at a constant speed of 50 km/hr while Swarup drives at 40 km/hr. If no time is wasted in transit, when will they meet again?
Answer & solution
- A
at 9:15 am
- B
at 9:18 am
- C
at 9:21 am
at 9:24 am
- E
at 9:30 am
At 4 km/hr, Arup walks 2 km in ½ hour = 30 minutes and at 50 km/hr, he covers 20 km in â hours = 24 minutes.
At 5 km/hr, Swarup walks 2 km in â hours = 40 minutes and at 40 km/hr, he covers 20 km in ½ hour = 30 minutes.
Thus, time taken by each of them to reach B is equal.
∴ Initially Swarup will go ahead of Arup and both of them will reach the finish line together.
Time = 30 + 30 + 24 = 84 minutes.
So, they meet again at 9:24 AM.
Hence, option (d).