XAT 2019 — QA & DI Question 11
Basics of QuadrilateralsEasy
In the trapezium ABCD the sides AB and CD are parallel. The value of is
âââââââ
Answer & solution
AD/AC
- B
AB/CD
- C
BC/AD
- D
AC/AD
- E
AC/CD
Solution
Refer the diagram below:

In âACL,
Sin∠BAC = Sin∠LAC = perpendicular/hypotenuse = CL/AC …(1)
Similarly, in âADM,
Sin∠BAD = Sin∠MAD = DM/AD …(2)
(1) ÷ (2)
⇒ Sin∠BAC : Sin∠BAD = CL/AC : DM/AD
Now, CL = DM
Hence, Sin∠BAC : Sin∠BAD = 1/AC : 1/AD = AD : AC
Hence, option (a).