XAT 2023 — QA & DI Question 4
TrianglesEasy
ABC is a triangle with BC = 5. D is thefoot of the perpendicular from A on BC. E is a point on CD such that BE = 3.
The value of AB2 - AE2 + 6CD is:
Answer & solution
- A
5
- B
10
- C
14
- D
18
21
Solution
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Given, BC = 5 and BE = 3
In â³ABD ⇒ AB2 = AD2 + BD2 ...(1)
In â³AED ⇒ AE2 = AD2 + DE2 ...(2)
(1) - (2)
⇒ AB2 - AE2 = BD2 - DE2
⇒ AB2 - AE2 = x2 - (3 - x)2
⇒ AB2 - AE2 = x2 - 9 - x2 + 6x
⇒ AB2 - AE2 = - 9 + 6x
We need to find AB2 - AE2 + 6CD
= (-9 + 6x) + 6 × (5 - x)
= -9 + 6x + 30 - 6x
= 21
Hence, option (e).