CAT 1991 — QA Question 40
Every day Neera’s husband meets her at the city railway station at 6.00 p.m. and drives her to their residence. One day she left early from the office and reached the railway station at 5.00 p.m. She started walking towards her home, met her husband coming from their residence on the way and they reached home 10 minutes earlier than the usual time. For how long did she walk?
Answer & solution
Correct answer: 55 minutes
- A
1 hour
- B
50 minutes
- C
1/2 hour
55 minutes
Since her husband meets her mid way, the total time saved by him can be equally divided into time saved while going to station and that saved while returning home.
In other words, he saved 5 mins while going and 5 mins while coming.
So instead of usual time of 6:00 pm he must have met her at 5:55 pm.
So she must have walked for 55 mins.
Hence, option (d).