CAT 1994 — QA Question 27

Let log₆ 216$\sqrt{6}$ = x.

Then by rule, log_b a = x ⇒ b^x = a we have,

6^x = 216√6

6^x = 6³ × $6^{\frac{1}{2}}$

⇒ 6^x = $6^{\frac{7}{2}}$

∴ x = $\frac{7}{2}$