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CAT 1995 — QA Question 37

Basics (Functions)Easy
Passage / Data

Directions for next 4 questions: Answer the questions based on the following information.

le(x, y) = Least of (x, y)
mo(x) = |x|
me(x, y) = Maximum of (x, y)

Find the value of me(a + mo(le(a, b)); mo(a + me(mo(a), mo(b))), at a = –2 and b = –3.

Answer & solution

Correct answer: 1

  • 1

  • B

    0

  • C

    5

  • D

    3

Solution

If a = –2 and b = –3, then our expression will be me(–2 + mo(le(–2, –3)), mo(–2 + me(mo(–2), mo(–3)))
= me(–2 + mo(–3), mo(–2 + me(2, 3)))
= me(–2 + 3, mo(–2 + 3))
= me(1, mo(1)) = me(1, 1) = 1.

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CAT 1995 QA Q37: Find the value of me(a + mo(le(a, b)); mo(a + me(mo(a), mo(b))), at a = –2 and b = –3. — Solution | TheCATExam