CAT 2018 Slot 2QA Question 21

LogarithmsEasy

If p3 = q4 = r5 = s6, then the value of logs(pqr) is equal to

Answer & solution

Correct answer: 47/10

  • 47/10

  • B

    16/5

  • C

    24/5

  • D

    1

Solution

Easy

Set the common value to kk and write each variable as a power of kk. Then pqrpqr and ss are both powers of kk, so the logarithm is just a ratio of exponents.

1

Express each variable. Let p3=q4=r5=s6=kp^3=q^4=r^5=s^6=k.

p=k1/3,q=k1/4,r=k1/5,s=k1/6\begin{aligned} &p=k^{1/3},\quad q=k^{1/4},\quad r=k^{1/5},\quad s=k^{1/6} \end{aligned}
2

Combine for pqrpqr. Add the exponents over a common denominator 6060.

pqr=k13+14+1513+14+15=20+15+1260=4760 pqr=k47/60\begin{aligned} &pqr=k^{\frac13+\frac14+\frac15}\\ &\frac13+\frac14+\frac15=\frac{20+15+12}{60}=\frac{47}{60}\\ &\Rightarrow\ pqr=k^{47/60} \end{aligned}
3

Take the logarithm to base ss. With s=k1/6s=k^{1/6}, the log is the ratio of exponents.

logs(pqr)=logk1/6 ⁣(k47/60)=47/601/6=47606=4710\begin{aligned} &\log_s(pqr)=\log_{k^{1/6}}\!\big(k^{47/60}\big)=\frac{47/60}{1/6}\\ &=\frac{47}{60}\cdot 6=\frac{47}{10} \end{aligned}
logs(pqr)=4710\log_s(pqr)=\frac{47}{10}

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CAT 2018 Slot 2 QA Q21: If p 3 = q 4 = r 5 = s 6 , then the value of log s (pqr) is equal to — Solution | TheCATExam