Easy
Take logs to base 4. Since 17 is just above 16=42, log417 is just over 2, so n must just exceed 2×19=38 — the smallest integer is 39.
1
Take log4 of both sides.
4n>1719⇒ n>19log417
2
Estimate log417. Since 42=16<17, log417 is slightly more than 2 (about 2.043).
log417≈2.043⇒ 19log417≈38.8
3
Smallest integer above the bound.
n>38.8⇒ nmin=39
Check: 439=278 and 1719<(24.1)19=277.9, while 438=276<1719. So 39 is indeed the first integer to clear the bound.