CAT 2023 Slot 2DILR Question 13

Mixed PracticeEasy
Passage / Data

Answer the following questions based on the information given below:

Three participants – Akhil, Bimal and Chatur participate in a random draw competition for five days. Every day, each participant randomly picks up a ball numbered between 1 and 9. The number on the ball determines his score on that day. The total score of a participant is the sum of his scores attained in the five days. The total score of a day is the sum of participants’ scores on that day. The 2-day average on a day, except on Day 1, is the average of the total scores of that day and of the previous day. For example, if the total scores of Day 1 and Day 2 are 25 and 20, then the 2-day average on Day 2 is calculated as 22.5. Table 1 gives the 2-day averages for

Participants are ranked each day, with the person having the maximum score being awarded the minimum rank (1) on that day. If there is a tie, all participants with the tied score are awarded the best available rank. For example, if on a day Akhil, Bimal, and Chatur score 8, 7 and 7 respectively, then their ranks will be 1, 2 and 2 respectively on that day. These ranks are given in Table 2. 

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The following information is also known.

  1. Chatur always scores in multiples of 3. His score on Day 2 is the unique highest score in  the competition. His minimum score is observed only on Day 1, and it matches Akhil’s score on  Day 4.
  2. The total score on Day 3 is the same as the total score on Day 4.
  3. Bimal’s scores are the same on Day 1 and Day 3.

What is the minimum possible total score of Bimal?

Answer & solution

Answer: 25

Solution

Easy

From the shared grid, Bimal's total is 35(A2+A5)35-(A_2+A_5). To minimise it, maximise the two free Akhil cells.

From the set deduction: Bimal's total =35A2A5=35-A_2-A_5 with A2{4,5}A_2\in\{4,5\} and A5{4,5}A_5\in\{4,5\}.

1

Maximise the subtracted sum. Bimal's total shrinks as A2+A5A_2+A_5 grows. The largest allowed values are A2=5A_2=5 and A5=5A_5=5, giving A2+A5=10A_2+A_5=10.

2

Compute.

Bimalmin=3510=25.\text{Bimal}_{\min}=35-10=25.

Check: then Akhil =15+10=25=15+10=25, Chatur =30=30; daily totals stay 15,15,16,16,1815,15,16,16,18 — all consistent.

Minimum possible total score of Bimal =25=\mathbf{25}.

CAT 2023 Slot 2 DILR Q13: What is the minimum possible total score of Bimal? — Solution | TheCATExam