TheCATExam
Sign in

CAT 2024 Slot 3 — DILR Question 17

TablesEasy
Passage / Data

Answer the following questions based on the information given below.

The table given below shows the amount, in grams, of carbohydrate, protein, fat and all other nutrients, per 100 grams of nutrients in seven foodgrains. The first column shows the foodgrain category and the second column its codename. The table has some missing values.

Table of carbohydrate, protein, fat and other nutrients per 100 g for seven foodgrains

CategoryCodenameCarbohydrateProteinFatOther nutrients
CerealC1——012
CerealC2——310
MilletM16210——
MilletM2——716
MilletM356—12—
Pseudo-cerealP166——10
Pseudo-cerealP2—14—8

The following additional facts are known.
1. Both the pseudo-cereals had higher amounts of carbohydrate as well as higher amounts of protein than any millet.
2. Both the cereals had higher amounts of carbohydrate than any pseudo-cereal.
3. All the missing values of carbohydrate amounts (in grams) for all the foodgrains are non-zero multiples of 5.
4. All the missing values of protein, fat and other nutrients amounts (in grams) for all the foodgrains are non-zero multiples of 4.
5. P1 contained double the amount of protein that M3 contains.

How many grams of other nutrients were there in 100 grams of nutrients in M3?

Answer & solution

Correct answer: 24

Answer: 24

Solution

Medium

M3's protein comes from Fact 5 (P1 = 2×M3 protein) together with Fact 1; then the row total fixes the “other nutrients” cell.

M3: carb =56=56, fat =12=12, so protein ++ other =32=32. P1: carb =66=66, other =10=10, so protein ++ fat =24=24. Fact 5: P1 protein =2×=2\timesM3 protein; all are non-zero multiples of 4.

1

Find M3 protein. P1 protein must beat every millet protein (max so far 12, Fact 1), so P1 protein ≥16\ge16; with Fact 5 and non-zero fat, M3 protein =8=8 (so P1 protein =16=16, P1 fat =8=8).

P1 protein=2×M3 protein(Fact 5)⇒ M3 protein=8, P1 protein=16 (>12, Fact 1)\begin{aligned} &\text{P1 protein}=2\times\text{M3 protein} \quad\text{(Fact 5)}\\ &\Rightarrow\ \text{M3 protein}=8,\ \text{P1 protein}=16\ (>12,\ \text{Fact 1}) \end{aligned}
2

Other nutrients in M3. Use the 100 g total.

other=100−56−8−12⇒ 24\begin{aligned} &\text{other}=100-56-8-12\\ &\Rightarrow\ 24 \end{aligned}
24 g24 \text{ g}

Related Tables questions

See all Tables & Graphs questions →
CAT 2024 Slot 3 DILR Q17: How many grams of other nutrients were there in 100 grams of nutrients in M3? — Solution | TheCATExam