XAT 2014 — Decision Making Question 3
Read the following case – let and answer the questions that follow.
Ms. Banerjee, class teacher for 12th standard, wants to send teams (based on past performance) of three students each to district, state, national, and international competition in mathematics. Till now, every student of the class has appeared in 100 school level tests. The students had following distribution of marks in the tests, in terms of “average” and “number of times a student scored cent per cent marks”.
Ms. Banerjee has carefully studied chances of her school winning each of the competitions. Based on in-depth calculations, she realized that her school is quite likely to win district level competition but has low chances of winning the international competition. She listed down the following probabilities of wins for different competitions. Prize was highest for international competition and lowest for district level competition (in that order).
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All the students are studying in the school for last twelve years. She wanted to select the best team for all four competitions (Ms. Banerjee had no other information to select students).
Ms. Banerjee has to select the team for national competition after she has selected the team for international competition. A student selected for international competition cannot be a part of national competition. Which is the best team for the national competition?
Answer & solution
- A
1, 7, 4
- B
8, 9, 10
- C
2, 8, 14
3, 6, 1
- E
Any of remaining students, as it would not matter
A student selected for international competition cannot be selected for national competition. So, students 2, 8 and 14 cannot be a part of national team. The probability of winning in the national competition is 10%. So, here the stress should be on the number of times cent percent is scored.
Also, the students with higher averages are preferred.
Option (1) has students having high averages but lesser cent percent scores.
Option (2) has students having lower average scores like 60.
Option (3) has all the students having an average score of 60.
Option (4) has students having higher averages of 65 and 70. Also, their combined cent percent scores is very high, 8 + 10 + 7 = 25.
Hence, option (d).