CAT 1991 — QA Question 29
Basics (Functions)Easy
Let Y = minimum of {(x + 2), (3 – x)}. What is the maximum value of Y for 0 ≤ x ≤ 1?
Answer & solution
Correct answer: 2.5
- A
1.0
- B
1.5
- C
3.1
2.5
Solution
For Y to be maximum,
x + 2 = 3 - x
∴ x = 0.5
Maximum value of Y = x + 2 = 2.5
Hence, option (d).
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