CAT 2002 — DILR Question 16

There are 10 employees who are engaged in both complex and medium operations.

For employee 2001148:

The amount earned in Medium operations = 513.26 − 51.53 − 3 = 458.73

$\frac{51.53}{3.33}<\frac{458.73}{1.67}$

For employee 2001151:

The amount earned in Medium operations = 282.81 − 171.71 − 79.1 = 32

$\frac{171.71}{5.5}>\frac{32}{4}$

For employee 2001155:

The amount earned in Medium operations = 597.94 − 497.47 − 100.47 = 0

Hence, the average amount earned per day in Medium operations = 0/4.67 = 0

Hence, the average amount earned per day in Complex operations is more.

For employee 2001159:

$\frac{594.43}{9.67}>\frac{159.64}{13.33}$

For employee 2001162:

$\frac{472.51}{1.29}>\frac{109.73}{9.71}$

For employee 2001165:

$\frac{402.25}{5.27}>\frac{735.72}{12.07}$

For employee 2001169:

$\frac{288.48}{8.38}>\frac{6.1}{4.25}$

For employee 2001170:

$\frac{812.1}{10}>\frac{117.46}{8.5}$

For employee 2001177:

$\frac{46.56}{2}<\frac{726.19}{19}$

For employee 2001180:

$\frac{116.4}{5}<\frac{1262.79}{19}$

∴ There are 7 employees for whom per day earnings in complex operations is more than per day earnings in medium operations.

Hence, option (d).