CAT 2017 Slot 1QA Question 22

Number TheoryEasy

If x + 1 = x2 and x > 0, then 2x4 is:

Answer & solution

Correct answer: 7 + 3√5

  • A

    6 + 4√5

  • B

    3 + 5√5

  • C

    5 + 3√5

  • 7 + 3√5

Solution

Easy

Don't compute x4x^4 from the surd directly — keep reusing x2=x+1x^2=x+1 to fold powers down. Square the relation to express x4x^4 linearly in xx, then substitute x=1+52x=\tfrac{1+\sqrt5}{2}.

1

Find xx. Rearrange x+1=x2x+1=x^2 and take the positive root:

x2x1=0 x=1+52(x>0)\begin{aligned} &x^2-x-1=0\\ &\Rightarrow\ x=\frac{1+\sqrt5}{2} \quad\text{(}x>0\text{)} \end{aligned}
2

Reduce x4x^4 to a linear expression. Square the given relation, then replace x2x^2 by x+1x+1:

x4=(x2)2=(x+1)2=x2+2x+1 x4=(x+1)+2x+1(x2=x+1) x4=3x+2\begin{aligned} &x^4=(x^2)^2=(x+1)^2=x^2+2x+1\\ &\Rightarrow\ x^4=(x+1)+2x+1 \quad\text{(}x^2=x+1\text{)}\\ &\Rightarrow\ x^4=3x+2 \end{aligned}
3

Compute 2x42x^4. Double, then substitute xx from step 1:

2x4=6x+4 61+52+4=3(1+5)+4 3+35+4=7+35\begin{aligned} &2x^4=6x+4\\ &\Rightarrow\ 6\cdot\frac{1+\sqrt5}{2}+4=3(1+\sqrt5)+4\\ &\Rightarrow\ 3+3\sqrt5+4=7+3\sqrt5 \end{aligned}
2x4=7+352x^4=7+3\sqrt5

Related Number Theory questions

See all Number Theory questions →
CAT 2017 Slot 1 QA Q22: If x + 1 = x 2 and x > 0, then 2x 4 is: — Solution | TheCATExam