CAT 2017 Slot 2QA Question 23

Composite FunctionsEasy

Let f(x) = x2 and g(x) = 2x, for all real x. Then the value of f(f(g(x)) + g(f(x))) at x = 1 is

Answer & solution

Correct answer: 36

  • A

    16

  • B

    18

  • 36

  • D

    40

Solution

Easy

Evaluate from the inside out at x=1x=1: compute f(g(1))f(g(1)) and g(f(1))g(f(1)), add them, then apply the outer ff (squaring) to that sum.

1

Inner pieces at x=1x=1. Here f(x)=x2f(x)=x^2 and g(x)=2xg(x)=2^x.

g(1)=21=2    f(g(1))=f(2)=22=4f(1)=12=1    g(f(1))=g(1)=21=2\begin{aligned} &g(1) = 2^1 = 2 \;\Rightarrow\; f(g(1)) = f(2) = 2^2 = 4\\ &f(1) = 1^2 = 1 \;\Rightarrow\; g(f(1)) = g(1) = 2^1 = 2 \end{aligned}
2

Add the two pieces. Sum the results from step 1.

f(g(1))+g(f(1))=4+2=6\begin{aligned} &f(g(1)) + g(f(1)) = 4 + 2 = 6 \end{aligned}
3

Apply the outer ff. Square the sum.

f(6)=62=36\begin{aligned} &f(6) = 6^2 = 36 \end{aligned}
f(f(g(x))+g(f(x)))x=1=36f\big(f(g(x))+g(f(x))\big)\big|_{x=1} = 36

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CAT 2017 Slot 2 QA Q23: Let f(x) = x 2 and g(x) = 2x, for all real x. Then the value of f(f(g(x)) + g(f(x))) at x = 1 is — Solution | TheCATExam