CAT 2017 Slot 2QA Question 24

Forming a Quadratic Equation and Relation between roots and coefficientsEasy

The minimum possible value of the squares of the roots of the equation: x2 + (a + 3)x – (a + 5) = 0 is

Answer & solution

  • A

    1

  • B

    2

  • 3

  • D

    4

Solution

In the given equation, let α and β be the 2 roots of the equation  Now α + β = - (a + 3)

Also α × β = - (a – 5)

(α + β)2 = α+ β+ 2αβ

⇒ (a + 3)2 = α+ β2 - 2(a + 5)
​​​​​​​⇒ a2 + 6a + 9 = α2 + β2 - 2a – 10
⇒ a2 + 8a + 19 = α2 + β2
⇒ (a2 + 8a + 16) + 3 = α2 + β2
⇒ α2 + β2 = (a + 4)2 + 3

Now (a + 4)2 ≥ 0

So minimum value of (a + 4)2 will be 0 when a = -4

At a = -4, the of squares of the roots of the equation i.e., α2 + β2 will be 3.

Hence, option (c).

CAT 2017 Slot 2 QA Q24: The minimum possible value of the squares of the roots of the equation: x 2 + (a + 3)x – (a + 5) = 0 is — Solution | TheCATExam