CAT 2017 Slot 2QA Question 31

Basics (Functions)Easy

If f(ab) = f(a)f(b) for all positive integers a and b, then the largest possible value of f(1) is

Answer & solution

Correct answer: 1

Answer: 1

Solution

Easy

Substitute a=b=1a=b=1 into the functional equation. This forces a simple equation in f(1)f(1) alone, whose largest solution is the answer.

1

Plug in a=b=1a=b=1. Then ab=1ab=1, so the relation f(ab)=f(a)f(b)f(ab)=f(a)f(b) becomes an equation in f(1)f(1). Let x=f(1)x=f(1).

f(11)=f(1)f(1) x=xx x2x=0\begin{aligned} &f(1\cdot 1)=f(1)\,f(1)\\ &\Rightarrow\ x=x\cdot x\\ &\Rightarrow\ x^2-x=0 \end{aligned}
2

Solve for xx. Factor.

x(x1)=0 x=0orx=1\begin{aligned} &x(x-1)=0\\ &\Rightarrow\ x=0\quad\text{or}\quad x=1 \end{aligned}

The largest possible value of f(1)f(1) is therefore 11.

f(1)max=1f(1)_{\max}=1

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CAT 2017 Slot 2 QA Q31: If f(ab) = f(a)f(b) for all positive integers a and b, then the largest possible value of f(1) is — Solution | TheCATExam